How do you calculate the m of sulphuric acid needed to react with 7.79g of copper oxide(II)?

First get the number moles in 7.79g of Copper oxide (III). In order for enough sulphuric acid to react with copper oxide you need the molar ratio to be equal to 1. So the number of moles of copper oxide should be the same as that of sulphuric acid. Now that you have the number of moles (= moles of copper oxide), calculate how many grams of sulphuric acid that number of moles is equal to. That is the m of sulphuric acid you need. Hope this helps :)